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Najlepsze rozwiązanie

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  ewka13 21.12.2011 (16:08)

  a)chlorek sodu
  
  2Na + Cl_{2} \to 2NaCl
  
  2Na + 2HCl \to 2NaCl + H_{2}\uparrow
  
  Na_{2}O + 2HCl \to 2NaCl + H_{2}O
  
  NaOH + HCl \to NaCl + H_{2}O
  
  Na_{2}CO_{3} + 2HCl \to 2NaCl + H_{2}O + CO_{2}\uparrow
  
  2NaOH + MgCl_{2} \to 2NaCl + \downarrow Mg(OH)_{2}
  
  2Na + CuCl_{2} \to 2NaCl + Cu
  
  Na_{2}SO_{4} + BaCl_{2} \to 2NaCl + \downarrow BaSO_{4}
  
  b)siarczan (VI) glinu
  
  2Al + 3H_{2}SO_{4} \to Al_{2}(SO_{4})_{3} + 3H_{2}\uparrow
  
  Al_{2}O_{3} + 3H_{2}SO_{4} \to Al_{2}(SO_{4})_{3} + 3H_{2}O
  
  2Al(OH)_{3} + 3H_{2}SO_{4} \to Al_{2}(SO_{4})_{3} + 6H_{2}O
  
  Al_{2}O_{3} + 3SO_{3} \to Al_{2}(SO_{4})_{3}
  
  2Al(OH)_{3} + 3SO_{3} \to Al_{2}(SO_{4})_{3} + 3H_{2}O
  
  Al_{2}(CO_{3})_{3} + 3H_{2}SO_{4} \to Al_{2}(SO_{4})_{3} + 3H_{2}O + 3CO_{2}\uparrow
  
  2Al + Au_{2}(SO_{4})_{3} \to Al_{2}(SO_{4})_{3} + 2Au
  
  2AlCl_{3} + 3Ag_{2}SO_{4} \to Al_{2}(SO_{4})_{3} + \downarrow 6AgCl.

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