Treść zadania

Najlepsze rozwiązanie

• 

  3 0

  ewka13 16.6.2011 (21:53)

  Zad 1.
  P = 2\cdot2cm\cdot4cm + 2\cdot2cm\cdot 6cm+ 2\cdot 4cm\cdot6cm =
  
  = 16cm^{2}+24cm^{2}+48cm^{2}= 88cm^{2}
  
  P = 2\cdot4cm\cdot1cm +2\cdot1cm\cdot6cm +2\cdot4cm\cdot6cm=
  
  =8cm^{2} +12cm^{2} + 48cm^{2} = 68cm^{2}
  
  P = 2\cdot1cm\cdot2cm + 2\cdot1cm\cdot6cm + 2\cdot2cm\cdot6cm =
  
  =4cm^{2} + 12cm^{2} + 24cm^{2} = 40cm^{2}
  
  Zad 2.
  Pole sześcianu :
  
  P=6a^{2}
  
  a)
  P = 6mm^{2}6a^{2} = 6mm^{2}
  
  a^{2} = 1mm^{2}
  
  a = 1mm
  
  b)
  P = 24cm^{2}
  
  6a^{2} = 24cm^{2}
  
  a^{2} = 4cm^{2}
  
  a = 2cm
  
  c)
  P = 150m^{2}
  
  6a^{2} = 150m^{2}
  
  a^{2} = 150m^{2} : 6
  
  a^{2} = 25m^{2}
  
  a = 5m

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